Question: Given that the points (-2,8), (1,1) and (3,k) lie on a straight line, calculate the value of k.
Note: Please help me. I know that the 1st number of each are the x-values so k is a y-value. How do I solve this but also how do I clearly show the working?
Could you please take me through the steps of finding out what k is (the value). Thankyou so much for your help.
Question 2: I need to express the equation x/3 + y/6 = 1 in the form y=mx+c
What is the answer? What I did, was I multiplied the x/3 by two so that the denominator of the fraction was 6 like y/6. I then multiplied the 2x/6, y/6 and 1 by 6 so that the two (y and 2x) on the left hand side of the equals sign were whole numbers. I subtracted 2 x from the left hand side so it was -2x on the right hand side. This worked out to: y=-2x+6 Is this correct?
Thankyou!
2007-02-07
21:36:15
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5 answers
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