A 45 kg girl is standing on a 150 kg plank. The plank, originally at rest, is free to slide on a frozen lake, which is a flat, frictionless surface. The girl begins to walk along the plank at a constant velocity of 1.5 m/s to the right relative to the plank.
A) what is her velocity relative to the surface of the ice?
B) What is the velocity of the plank relative to the surface of the ice?
I'm confused. I'm pretty sure I'm doing it right, yet I'm getting the wrong answer.
Here's what I'm doing:
M(girl)=45kg
M(plank)=150kg
V(girl)[initial]=0
V(plank)[initial]=0
V(girl)[final]=1.5
V(plank)[final]=?
M(girl)V(girl)[initial] + M(plank)V(plank)[initial] = M(girl)V(girl)[final] + M(plank)V(plank)[final]
So: 0 + 0 = (45)(1.50) + (150)(V)
So: 0 = 67.5 + 150(V)
So: 67.5 = -150(V)
So: V = -.45 <- Final Plank velocity.
So if the girl is moving 1.50 m/s, and the plank is moving -.45 m/s. Wouldn't her velocity relative to the ice be 1.50 - .45 = 1.05?
Book answers:
a) 1.15 m/s
b) -0.346 m/s
2007-12-18
13:58:52
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2 answers
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asked by
mew1033
2
in
Physics