the lenght of a rectangle is 4ab. the width is 2ab. find the perimeter of the rectangle in terms of ab. please show work or at least enough to show me how to do it.
2007-12-18 14:25:28 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The perimeter of a rectangle is simply the sum of the lengths of its sides. It has 2 sides of length 4ab and 2 sides of length 2ab, so the perimeter is 2*4ab + 2*2ab = 12ab.
2007-12-18 14:28:44 · answer #1 · answered by Pascal 7 · 1⤊ 0⤋
draw a picture of it and it will be obvious that
each side is 4ab for a sub-total of 8ab
top and bottom are each 2ab for a sub-total of 4ab
adding the two subtotals is 8ab +4 ab or 12ab
2007-12-18 14:43:17 · answer #2 · answered by saejin 4 · 0⤊ 0⤋
...........................4ab
____________________
|.............................................|
.2ab....|.............................................|....2ab
|____________________|
............................4ab
please ignore the periods (.......) it is so the rectangle will line up well and look like a rectangle
recall that the perimeter of a shape is the distance around the outer edge of the shape... in this case it would be the top - 4ab plus the bottom - 4ab, plus the left side - 2ab, plus the right side - 2ab
4ab + 4ab + 2ab +2ab = 12ab
2007-12-18 14:37:54 · answer #3 · answered by Anonymous · 0⤊ 0⤋
perimeter = 2l + 2w
2(4ab) + 2(2ab) = 8ab + 4ab =
12ab
im pretty sure thats right.
2007-12-18 14:30:15 · answer #4 · answered by g2n 2 · 0⤊ 0⤋
4ab+4ab+2ab+2ab=12ab
2007-12-18 14:30:18 · answer #5 · answered by Anonymous · 0⤊ 0⤋