Hi,
I need to evaluate the integral of sin^3(2x)dx.
I started by using the power-reducing formula to turn sin^2 x into (1-cos 4x/2) and multiplying that by sin 2xdx.
So I have: ⌡ (1-cos 4x/2) (sin 2x) dx
Then I took the 1/2 out front to get:
1/2 ⌡ (1-cos 4x) (sin 2x) dx
Then I distributed the sin 2x out to get:
1/2 ⌡ (sin 2x - sin 2xcos4x) dx
Well, I wanted to use u-sub. with u = sin 2x and du = 2 cos 2x, but as you can see, I have cos 4x. How would I complete this problem (if I was on the right track in the first place)?
Thanks for the help! :>)
2007-12-18
00:15:48
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6 answers
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asked by
LLH
2
in
Mathematics