If I have two equally proportioned triangles (same angles, ratio of sides etc), if the area of one triangle is TWICE that of the other, what is the length of the base (S) of the large one in terms of the smaller (s).
I'm presuming triangle shape is immaterial; it's just that they're equivalent and one is 2x the area of the other; and presumably the answering equation relates to any of the sides you'd wish to compare.
The answer is S = (sqrt of 2) x s.
But how do I know this? Pls advise how I could have worked it out. I have no further data (ie about height etc).
Thanks.
2007-12-30
23:26:39
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5 answers
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asked by
Anonymous
in
Mathematics