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Write each expression as a sum and/or difference of logarithms. Express powers as factors.

(1) log_3 (x/9)

(2) log_7 (x^5)

NOTE: log_3 means "log base 3" and log_7 means "log base 7."

Got it?

2007-12-30 22:05:42 · 4 answers · asked by journey 1 in Science & Mathematics Mathematics

4 answers

log_3(x) - log_3 (3^2) = log_3(x) - 2

5log_7(x)

2007-12-30 22:22:52 · answer #1 · answered by timekiller finaly wireless 4 · 0 0

1. log_3 x - 2

2. 5log_7 x

2007-12-31 06:35:49 · answer #2 · answered by Steiner 7 · 0 0

1. log_3(x) -- 2
2. 5log_7(x)

2007-12-31 06:12:27 · answer #3 · answered by sv 7 · 0 0

logx-log9=(logx)-2
5logx

2007-12-31 06:11:09 · answer #4 · answered by someone else 7 · 0 0

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