I had a final in calc BCAP today and it was terrible. I keep running over the problems in my head.
Okay, it was something like "get the area between y=3x and y=(x^3)- (2x^2)"
I set 3x equal to [(x^3)- (2x^2)] I ended up with x=-1, x=0 and x=3. Then I was confused, thinking I'm only supposed to get two numbers. So I just used -1 for the lower limit and 3 for the upper. So it was (bear with me, no idea how to type this) a definite intergral with -1 and 3 as the limits and [(x^3)- (2x^2)-3x) dx.
thus, plugging the upper and lower limits in: (27-18-9)- (-1-2-3)= 6
2007-12-18
09:21:29
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2 answers
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asked by
Sophie
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Mathematics