7 < -2p+13
2007-12-18 09:47:05 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
First, subtract 13 from both sides.
-6 < -2p
Divide both sides by -2.
3 > p
You have to flip the sign when you divide or multiply by a negative number.
So your answer is p < 3.
Hope this helps!
2007-12-18 09:51:01 · answer #1 · answered by Viv 3 · 0⤊ 1⤋
7 < -2p+13
7-13 < -2p +13 -13
-6 < -2p
-6/-2 > p
3 > p
p < 3
2007-12-18 09:52:00 · answer #2 · answered by yassem1ne 2 · 0⤊ 0⤋
7 < -2p + 13
7 - 13 < -2p + 13 - 13
-6 < -2p
-6 / -2 > -2p / -2 (flip your < here because you are dividing by -)
3 > p
2007-12-18 09:52:43 · answer #3 · answered by ajordan971 5 · 0⤊ 1⤋
7 < -2p+13
-6 < -2p
-3 < -p
3 > p
2007-12-18 09:50:23 · answer #4 · answered by DWRead 7 · 1⤊ 0⤋
Add (2p-7) to both sides,
2p < 13-7
2p < 6
Divide both sides by 2,
p < 3
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Ideas: In this approach, you don't need to change the direction of the inequality sign.
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To the guy who thumps down my answer:
If you don't understand my approach, you need to learn it.
2007-12-18 09:50:34 · answer #5 · answered by sahsjing 7 · 3⤊ 1⤋
2p < 13 - 7
2p < 6
p < 3
2007-12-18 09:53:56 · answer #6 · answered by Como 7 · 3⤊ 0⤋