A tennis ball, starting from rest, rolls down the hill in the drawing. At the end of the hill the ball becomes airborne, leaving at an angle of 35° with respect to the ground. Treat the ball as a thin-walled spherical shell, and determine the range x.
I dont have a picture of the drawing but the ball rolls down a hill, goes back up slightly then launches at a angle of 35 degrees. the point at which the ball is launches is at the same height as where the ball lands. Also the vertical height from where the ball starts rolling down the hill to the height it is launched from is 1.8m.
I know the Inertia of a hollow shell sphere is I=(2/3)mr^2
2007-12-05
15:58:58
·
2 answers
·
asked by
Anonymous
in
Physics