given: ABCD is a parallelogram, line ABE, angle CBE is congruent to angle CEB.
prove: a. angle DAE is congruent to angle CEA
b. AECD is an isosceles trapezoid
i have a lot of problems with proofs; i really dont understand. any help would be greatly appreciated, thank you!
2007-12-05 15:56:38 · 4 answers · asked by redx 2 in Science & Mathematics ➔ Mathematics
Since ABCD is a ||-ogram, AD= BC and AD||BC by definition.
Thus angle DAE = angle CBE because they are corresponding angles formed by two || lines and a transversal.
Since it is given that angle CBE = angle CEB, then angle DAE must also = angle CEB (both equal to same angle).
Since it is given that angle CBE = angle CEB then triangle BEC is isosceles and hence BC= CE.
Thus AD = CE since they both equal BC.
Hence AECD is an isosceles trapezoid because its two non || sides are equal.
2007-12-05 16:13:46 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
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2016-09-30 23:38:12 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Did you have a diagram associated with this? Because I'm drawing this and it doesn't make much sense. Is point A opposite of C or D?
2007-12-05 16:06:23 · answer #3 · answered by Anonymous · 0⤊ 1⤋
not with that question wut did u say im confused with you
2007-12-05 15:58:58 · answer #4 · answered by Anonymous · 0⤊ 1⤋