Two kids sell lemonade on their street at separate concession stands. One kid sells at 2 cups for $1 and the other at 3 for $1. They each sell 30 cups one day, so Kid #1 makes $15 and Kid #2 makes $10.
The next day, Kid #2 gets sick and hands over his sales to Kid #1, and Kid #1 sells them for the same price that Kid #2 did, at 3 for $1, while still selling his own cups at 2 for $1. At a combined 5 for $2, he sells 60 cups, but only ends up with $24. How is that possible?
I'll try to simplify it for you with this little chart...
Day 1...
Kid #1: 30 @ 2 for $1=$15
Kid #2: 30 @ 3 for $1=$10
TOTAL SALES FOR DAY=$25
Day 2 (combined)...
Kid #1: 2 for $1+3 for $1=5 for $2
60 @ 5 for $2=$24
btw, the answer has nothing to do with making 5 for $2 from 3 for $1 and 2 for $1. If he alternates, he ends up getting $1 for 3 cups and $1 for 2 cups, so he ends up with $2 and sold 5 cups, which is 5 for $2.
MWAHAHAHAHA...
Can you solve it?
2006-12-28
17:26:32
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10 answers
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asked by
Anonymous
in
Jokes & Riddles