First, if i have an engine with 6.5 horsepower at 3600 rpm, the torque is measured from the outside of the crankshaft of diameter 3/4", right? so if i put a sprocket on to drive a chain i have to divide my torque of 9.48 ft-lbs by the ratio between 3/4 and the diameter of the sprocket? does this affect horsepower AND torque or does the hp stay the same due to the increased linear speed?
Also, if i am supplying a certain amount of torque and hp to the rear drive sprocket, how do i figure out how much "thrust" i am supplying to the ground, say if its 40 ft-lbs on the sprocket and the wheel is 2 times bigger, do i divide 40 ft-lbs by 2 and get 40 pounds force, or what?
Ive been trying to figure this out for awhile so the more detailed the better, thanks.
2007-11-17
18:37:14
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1 answers
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asked by
Jesse C
1