I asked this question last night and got an answer. The answer is totally appreciated, but my gut feel is there is something mathematically wrong here... I was expecting the wind speed to be upwards of 40km/hr, not .7km/hr. Would someone be able to review the math used in the answer? Thank you kindly.
The Original Question...
Convert CFM to KMPH?
ok... I have a fan with a 36" diam capable of moving 10,354cfm. The fan is mounted in a round tube that tapers down to a 2'X2' square tube. Through the 2' x 2' section of tube, approximately what sort of wind speed can I expect? Also, can you provide a formula that can help me calculate this for different CFM values.
The Answer I got...
2' x 2' = 4 square foot cross section
10354 ft3/min / 4 ft2 = 2588.5 ft/min
2588.5 ft/min * 0.000305 km/ft = 0.7894925 km/hr
This, of course, asuumes 100% efficiency. I hope this helps you.
2007-11-17
16:33:44
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4 answers
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asked by
seanb_111
1
in
Science & Mathematics
➔ Engineering