A cable that is 26 feet long goes from the ground to the top of a building and forms an angle of 48.7o with the wall of the building. How many feet tall is the building?
2007-11-18 10:09:32 · 4 answers · asked by Angel 1 in Science & Mathematics ➔ Engineering
Draw a picture and label all dimensions provided. Below is my not-to-scale diagram using keyboard symbols.
H\ (this angle is 48.7°, not the angle at the ground)
H..\
H...\
H....\ (length of the hypotenuse is 26')
H.....\
H......\
H.......\ (this angle is 180° - 90° - 48.7° = 41.3°
The cable and the building make a right triangle. The angle between the cable and the building is 48.7°.
The hypotenuse is 26 feet, the length of the cable. We will assume that the ground is flat around the building.
Let H represent the height of the building.
H/26 = cos(48.7°)
H = cos(48.7°) * 26 feet = 17.1 feet.
H = cos(48.7) * 26 = 17.1'
H = sin(41.3) * 26 = 17.1 '
2007-11-18 10:46:50 · answer #1 · answered by Thomas C 6 · 1⤊ 0⤋
sin 48.7=x/26
x=26(sin48.7)
This is trig. of a right triangle.
Just took two classes of engineering math and in my third now. Try that it should work.
2007-11-18 18:40:56 · answer #2 · answered by seed2ofchuck 2 · 0⤊ 1⤋
Mr. Thomas C is right but both above him are totally wrong!!!!!
2007-11-19 03:25:30 · answer #3 · answered by Deepti 2 · 0⤊ 0⤋
22ft.
2007-11-18 18:18:04 · answer #4 · answered by hotmamas47 1 · 0⤊ 2⤋