Suppose a baseball is shot up from the ground straight up with an initial velocity of 32 feet per second. A function can be created by expressing distance above the ground,s, as a function of time,t. This function is s= -16t^2+ vot +so. 16 represents 1/2g, the gravitational pull due to gravity (measured in feet per second^2). vo is the intitial velocity (how hard do you throw the object, measured in feet per second^2). so is the initial distance above ground (in feet). If you are standing on the ground, then so=0. What is the function that describes this problem? The ball will be how high above the ground after 1 second? How long will it take to hit the ground? What is the maximum height of the ball? What time will the maximum hieght be attained?
2006-11-25
09:05:02
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3 answers
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asked by
Sydnie
1
in
Mathematics