At a temperature of 0 degrees celsius, the mass and volume of a fluid are 825 kg and 1.17 m^3. The coefficient of volume expansion is 1.26 x 10^-3 (degrees celsius)^-1. (a) what is the density of fluid at this temperature? (b) What is the density of the fluid when the temperature has risen to 20.0 degrees celsius?
My Approach:
(a) d = m/v = 825 kg/ 1.17m^3 = 705 kg/m^3
(b) d = (705 kg/m^3)(1.26 x 10^-3) (20 degrees celsius) = 17.8 kg/m^3
I really don't know what equation to use b/c my textbook is horrible in explaining these types of random problems! I appreciate all the help I can get
2006-11-14
17:18:00
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3 answers
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asked by
Anonymous
in
Physics