I am not entirely sure how it works. So, because of the difference of impedance b/t lets say a transmission line and a load creates a difference of voltage. To cross this voltage some of the energy of the signal is given up and the rest of the energy can't cross this distance and reflects back. I kinda don't get how the last part affects the signals. Is it just interference with the reflected waves when the incoming waves go through or does the energy loss across this potential effect the waveform.
Lets consider a 1,000 ohm source impedance, 50 ohm wire impedance, and 10,000,000 ohm oscilloscope impedance, which was used during class demonstration. The cable was connected where he put a resistor 50 ohm and a 50 ohm terminator to show reduction in the noise. Don't you apply the reflection coefficient to the source-cable junction and then scope-cable junction. I got for one (10M/50 -1 )/(10M/50-1) that would mean the cable is infinite and should not be much noise.
2007-09-12
17:20:21
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2 answers
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Anonymous