Science & Mathematics - 26 September 2006

I need help on this problem:

(-2b - 9)/(b2 + 7b + 12) = b/(b + 3) + 2/(b + 4)

I tried doing this, but it was no good. Help please?

(-2b - 9)/(b2 + 7b + 12) = b/(b + 3) + 2/(b + 4)
(-2b-9)/(b+3)(b+4) = b(b+4)/(b + 3)(b + 4) + 2(b+3)/(b + 3)(b + 4)
(-2b - 9)/(b + 3)(b + 4) = (b^2+4b+2b+6)/(b + 3)(b + 4)
(-2b - 9) = (b^2+6b+6)
0 = b^2 +8b + 15
0 = (b+5)(b-3)
b = -5, 3

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