2006-09-26 16:30:42 · 7 answers · asked by elven_archer24 1 in Science & Mathematics ➔ Chemistry
First calculate the molecular weight of Ca3(PO4)2 using the periodic table. Then, divide 4.71 g by this value to determine how many moles of calcium phosphate you have. Next, multiply the number of moles by Avogadro's number and you have the total number of particles of calcium phosphate. Each calcium phosphate molecule has 3 Ca2+ ions, so multiply the final result above by 3 and you have the number of Ca2+ ions in 4.71 g.
2006-09-26 16:39:14 · answer #1 · answered by apolitical 3 · 0⤊ 0⤋
well let's break this down into 5 simple steps.
1. what the hell does this problem mean
2. why am i on here
3. why am i answering this question
4. ok let's get serious here and take an educated guess
5.(the answer)- well c and a are the first and third letters in the alphabet.... and 1+3=4.... 4+the 4.71 g = 8.71.....and you can figure out the rest since i've gotten you off to the best possible start you will receive. thank you.... i know....i am the science/math wiz. ;)
2006-09-26 16:36:19 · answer #2 · answered by seminolefan925 2 · 0⤊ 3⤋
MM Ca3(PO4)2 = 310.1876 g/mol
to get the moles of Ca+2 ions in there
4.71g(1mole/310.1876 g/mol)(3moles Ca/1moleCa3(PO4)2)
= 0.04555 mole
if you need it in grams then multiply it with the Ca molar mass
0.04555mole*(40.08g/mole) = 1.8256 g Ca
if you need it in molecules of Ca then multiply it with the Avogadros number...
0.04555 mole(6.022x10^23molecules/1mole) = 2.743x10^22 molecules
best answer?
2006-09-26 22:26:33 · answer #3 · answered by teroy 4 · 1⤊ 0⤋
How Many Ca
2016-10-02 10:25:10 · answer #4 · answered by ? 4 · 0⤊ 0⤋
Calculate the molecular weight of the calcium phosphate, and divide that into three times the atomic weight of calcium to get the weight percentage of calcium in the compound. Multiply that by the number of grams you have to get the actual mass of calcium present. Divide by the atomic weight of calcium to get the number of moles, and multiply that by Avogadro's number (6.023E23). Tedious, but not difficult. (If you work out the algebra, it appears that the atomic weight of calcium will cancel out.)
2006-09-26 16:39:25 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Ca^2H^2O^6S^2G^2 but only a guess
2016-03-17 03:18:37 · answer #6 · answered by Anonymous · 0⤊ 0⤋
If it isn't dissolved in something, then you don't have any ions.
2006-09-26 16:39:56 · answer #7 · answered by Mr Cellophane 6 · 0⤊ 0⤋