simple.
in algebra, you always have to do what you did on one side to the other side.
ON the left side. x is divided by two. So you have to multiply by two to get x by itself. But you multipy .5 by 2 also.
.5 is the same thing as 1/2. 2 * 1/2 is equal to 1.
so X is equal to one as your final answer, X =1.
x/2 = .5
x = (.5)*(2)
x = (1/2) * (2)
x = 1
2006-09-26 16:02:25
·
answer #1
·
answered by Kid A 3
·
1⤊
3⤋
x = - 10
-10 / 2 = -5
2006-09-26 16:02:48
·
answer #2
·
answered by Charlie Bravo 6
·
0⤊
0⤋
For those form of questions try this, As from the equation 5(x+2)(2x-a million)=0, it is obvious that 5 = 0 (this occasion can in no way exist, so overlook approximately it) (x+2) = 0 (2x-a million) = 0 Take the latter 2 x + 2 = 0 x = -2 and 2x - a million = 0 2x = a million x = a million/2
2016-12-18 17:41:32
·
answer #3
·
answered by osterman 4
·
0⤊
0⤋
x/2=-5 Cross multiply 2 &-5
x=(-5)(2)
x=-10
2006-09-27 02:25:18
·
answer #4
·
answered by Anonymous
·
0⤊
0⤋
it's just like answering this simple question:
" A number divided by 2 would give you a result of (-5), what number is it ? "
Clearly, x = -10 since (-10)/2 = -5.
Another way to solve it out, you simply MULTIPLY BOTH SIDES by 2, which gives you a resut x = -10 since 2*(-5) = -10.
2006-09-26 16:27:53
·
answer #5
·
answered by Hanz 2
·
0⤊
0⤋
x/2=-5
2*x=-5*2 (multiply 2 by both sides in order to solve for x)
x=-10
2006-09-26 16:13:21
·
answer #6
·
answered by Lil Cajun 1
·
0⤊
0⤋
x=-10
2006-09-26 16:03:37
·
answer #7
·
answered by x 1
·
0⤊
0⤋
in order to clear the denominator of 2, multiply each side by the same number (2), renaming the equation and removing the fraction. the result is x= -10
2006-09-26 16:27:02
·
answer #8
·
answered by runnerboy516 2
·
0⤊
0⤋
x/2 = -5
by multiplication property of equality,
we can multiply both sides be 2
(x/2)*2 = -5*2
2x/2 = -10
2/2=1 (identity property of multiplication)
therefore,
x = -10
2006-09-26 19:34:45
·
answer #9
·
answered by woof! 2
·
0⤊
0⤋
x/2 = -5
x/2 (2) = -5 (2)
x = -10
2006-09-26 16:11:25
·
answer #10
·
answered by sgrockergirl 2
·
0⤊
0⤋