I asked this question in the Physics section, and didn't get much help. I want to move a metre in exactly one second. I also want to start stationary and end that way too.
As you all know, distance=velocity*time for coasting, and while accelerating, distance=.5*acceleration*time^2
I would like to acclerate for a period, perhaps coast for a bit, and then deccelerate equally and oppositely, so my accelerations will be a, 0, then -a for the three stages of this movement. What my real question is, and I apologize if I've beat around the bush, is what is the relationship between acceleration and distance coasted. If you can express one as a function of the other, great, and it would be even better if you could solve in terms of T and D, intstead of using 1 second and 1 metre for those values.
2007-02-10
01:24:56
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3 answers
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asked by
Mehoo
3
in
Mathematics