2007-02-10 01:23:24 · 6 answers · asked by sbaig_27 1 in Science & Mathematics ➔ Chemistry
AT O CELCIUS AND UNDER NORMAL PRESSURE WATER IS SOLID STAE i.e ICE.
AT 373 KELVIN i.e 100CELCIUS AND UNDER 1 ATM PRESSURE WATER IS BOILING i.e TRANSFORMATION FROM WATER 2 STEAM
2007-02-10 01:29:48 · answer #1 · answered by Anonymous · 0⤊ 1⤋
Pure water (without dissolved solids) will freeze at 0 C. so, at 0 C and at atmospheric pressure, water and ice mixture may exist. So, water can be in two phases, solid and liquid (OK, a small amount of water vapor will also be there). At 100 C, water again pure and at atmospheric pressure (760 m of Hg, mercury) will be a boiling liquid and steam combination (there will be no ice!). 373 K is 100 Celsius.
2007-02-10 01:50:07 · answer #2 · answered by Swamy 7 · 0⤊ 1⤋
Assuming standard pressure:
At 0C...water is at a phase change between solid and liquid.
At 373 K (99.85 C), water is a liquid and will start to boil soon if you don't keep watching the darn pot.
2007-02-10 01:28:37 · answer #3 · answered by gebobs 6 · 2⤊ 0⤋
Assuming one atmosphere pressure, it depends on the about of latent heat present. The amount of latent heat (which cannot be measured with a thermometer) will determine whether it is solid or liquid.
2007-02-10 01:33:30 · answer #4 · answered by P K 3 · 0⤊ 0⤋
I am looking at a potential 'trick' question here.
Zero is the change temp., however, 'water' at zero is 'water'. Water is the liquid state of H2O.
'Ice' at zero would be 'ice'.
Get an "A".
2007-02-10 06:41:48 · answer #5 · answered by teachr 5 · 0⤊ 0⤋
0C = freezing point
373K = 100C = Boiling point
2007-02-10 01:27:47 · answer #6 · answered by cato___ 7 · 1⤊ 1⤋