I read about a strange triple play in a baseball forum. The guy said he read about it in a baseball digest: this supposedly happened in a minor-league game in the 1950s. There was a TP in which no fielder touched the ball. The bases are loaded and the runners are going on the pitch. The batter hits an infield pop-up. The umpire immediately invokes the infield-fly rule; the batter is automatically out (out #1). The runner from 1st keeps going and passes the runner on second, who apparently either has frozen or is moving back toward the bag (the runner from 1st is out #2). Then the ball lands on the runner from 1st (out #3). The shortstop gets credit for all 3 outs since he was the closest fielder to the play. BUT, how can the runner from 1st make two outs? You can't be out twice. I think it happened like this: Out #2: the runner from 1st passes the runner on 2nd, who is trying to get back to 2nd. The runner on 2nd stumbles and the the ball lands on him, thus he is the 3rd out. Right?
2006-06-22
22:27:35
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8 answers
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asked by
♣Tascalcoán♣
4
in
Baseball