i was thinking if someonesolved it for me (at least once) then i will get an idea how it works and know how to work the problem so heres the problem, i was trying to find the voltage discharge in a cpapcitor and i found the formula and i couldn't figure it out so here you go
V=v(e^t/T)
the instintanious voltage is equal to the initial voltage times exponent to the power of time over tau
and now for the details
the capacitor has the capacitance of 80uf and has a rated voltage of 330v and the battery i am charging the capacitor with has 1.5 volts and 5.0 amps and i wanted to see how much the capacitor discharges in 1 second
2006-11-20
03:05:19
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4 answers
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asked by
macgyver
1