Science & Mathematics - 30 October 2006

20.00cm^3 of KI solution of unknown concentration is titrated with 0.0250M KMnO4 solution in the presence of excess acid. 14.80cm^3 of the KMnO4 solution is required for complete reaction. Calculate the concentration of the KI solution.
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My workings out so far:
n = cV

first part:
n(KMnO4) = 0.0250 x 14.80 = 0.37
c(KI) = 0.37/20 = 0.0185

The answer has to be 0.0925M
If you divide 0.37 by 4 then the answer comes out, but I'm not sure how to do it. I'd really appreciate some help!!!

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