Hello,
I was wondering how one would solve a trigonometric equation such as the following:
cos x = sin 2x, (0 =< x =< 2pi)
For this equation, I ended up with:
sin x = 1/2,
x = pi/6, 5pi/6
However, the answers supplied with the question have 5 answers, 0, pi, 2pi, pi/6 and 5pi/6. How do I get the additional 3 answers?
Same goes for the next one:
sin 2x = sqrt(3) cos x, (0 =< x =< 2pi)
I end up with:
sin x = [sqrt(3)]/2
x = pi/3, 2pi/3
The answers are pi/3, pi/2, 2pi/3, 3pi/2
Thank you very much.
2007-11-17
19:39:18
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2 answers
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asked by
w_gy_cc
2
in
Mathematics