i found out that:
x(man)t(catch)=x(bus)t(catch)
and
-b+ct(catch)=(1/2)at^2(catch)
A man is running at speed c (much less than the speed of light) to catch a bus already at a stop. At t=0 , when he is a distance b from the door to the bus, the bus starts moving with the positive acceleration a .
Use a coordinate system with x=0 at the door of the stopped bus.
So,
What is the minimum value of c for which the man will catch the bus?
Express the minimum value for the man's speed in terms of a and b ?
PLEASE clear explanations...thanks
2007-09-16
02:25:09
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2 answers
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asked by
Tommy
2
in
Physics