Imagine a row of 10 pirates, all very intelligent and all very greedy. We'll label the pirates with numbers 1 through 10.
The pirates are about to divide 100 gold coins among them in the following manner: Pirate #1 proposes how to divide the coins and his proposal is put to a vote (the proposing pirate also votes). If the vote passes, (tied vote also passes) then the coins are divided as per his proposal. Otherwise, he is thrown overboard and pirate #2 makes a new proposal, and so on.
How will the coins be divided? (Yes, there is a logical clear-cut, no-doubt-about-it solution)
2007-03-13
23:41:24
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10 answers
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asked by
pjjuster
2
in
Mathematics