1. The sum of the first and third terms of a geometric progression is 2/1/2.Given that the first term is 1/2,find the possible values of the common ratio,r, of the progression. In the case where r > 0,determine the last term of the progression which is less than 1 000
2. Given that p,q and r are three consecutive positive terms of a geometric progression. Express q in terms of p and r.
3. x,y,2/3,z and 2/27 are five consecutive terms of a geometric progression.Find the possible values of x,y and z.
4. The ratio of the sum of the second and third tems of geometric progression to its fourth term is 3:4. Show that 3r² - 4r - 4 = 0, where r is the common ratio. If r > 0 and the fifth term of this progression is 48, find the tenth term.
lol! i know this is a long question but please help me. Explain to me would be better. ^o^"'
thx to everyone who answered. (^_^)
2007-01-13
21:08:09
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4 answers
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asked by
woolala
2
in
Mathematics