The numbers Rsub1, Rsub2, and Rsub3 and R satisfy the following equation: (1/Rsub1)+(1/Rsub2)+(1/Rsub3)=(1/R).
A. If Rsub1=1 and Rsub2=2 and Rsub3=3, compute R exactly.
B. If both Rsub1 and Rsub2 are held constant, and Rsub3 is increased by .05, what is the approximate change in R?
Ok, I got part a, that's simple enough. I realize you can solve this easily using a calculator, But how do you do B by using linear approximation?
2007-10-30
11:08:37
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1 answers
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asked by
Anonymous
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Mathematics