in an effort to better understand how calculus works (instead of just solving problems), i have a maybe simple-maybe difficult question to ask regarding u substitution.
In integration, when you set something equal to u, why must you take du/dx. How exactly does that work? To make my Q clearer, here is an example.
definite integral of [(3x^2 + 2x)/(x^3 + x^2)]dx
u = x^3 + x^2
du = (3x^2 + 2x) dx <-----------what exactly is going on here??
integral du/u is ln|u| so answer is ln|x^3 + x^2|...
Sorry if this question sucked, but I really would like to know more in depth...
2007-08-22
20:50:25
·
6 answers
·
asked by
LIFE HATER
1
in
Mathematics