In a triangle with vertices ABC and center point O, there exists 3 medians. AMa, BMb, and CMc. If AMa = 156 and CMc = 204, can the triangle be solved and how? I say it cannot be solved but my teacher says it can
If it cannot be solved, then what are at least 2 triangles that use those medians so I can show it has at least more than one answer.
I can solve the medians into parts:
AO= 104
OMa = 52
CO = 136
OMc = 68
But that is about it
I have looked at working with a parallelogram involving OMa and a/2 seeking to use a^2 + b^2 + c^2 + d^2 = x^2 + y^2 where a, b, c, d are the parallelogram sides and x and y are the parallelogram diagonals. I have tried to use the equal areas of the six small triangles also with no luck. I solved AOMc and COMa for cos theta and solved the equations against each other but that left me with 2 unknowns
2007-02-03
06:12:18
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4 answers
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asked by
Phuzzy
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in
Mathematics