Once again, look at Alexander's question and the follow up question:
http://answers.yahoo.com/question/index;_ylt=ArVMRKyqf5weyNEklQHMoXDsy6IX?qid=20070515120146AA2qnnG
Now, we have twins A and B, both with wristwatches, set at noon at the time twin B departs. Twin A remains stationary. Twin B travels at speed (1/2)c for 1 hour, and returns at speed (1/2)c for 1 hour, per twin A's watch, so that A's watch now shows 2 pm. Both A and B have telescopes trained on each other's wristwatches. What is the function of times B(Ta) and A(Tb), where B is B's time as seen by A in A's time Ta, and A is A's time as seen by B in B's time Tb?
I wish the answer to this would be explained more often to those totally puzzled by the Twin Paradox. Are functions B(Ta) and A(Tb) symmetrical?
2007-05-15
11:51:15
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2 answers
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asked by
Scythian1950
7
in
Physics