A 71.4 kg man steps off a platform 3.49 m above the ground. He keeps his legs straight as he falls, but at the moment his feet touch the ground his knees begin to bend, and, treated as a particle, he moves an additional 0.59 m before coming to rest. Treating our rigid legged friend as a particle, what is the average force his feet exert on the ground while he slows down?
Assume the acceleration while he is slowing down is constant.
Answer= 4839 N. How do you do this?
2007-02-18
05:08:36
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2 answers
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asked by
soulen3
2
in
Physics