You have a Flask. The bottom part of the flask is in the shape of a truncated cone with bottom radius of 10 cm, top radius 5 cm, height 10 cm. Sitting on top of the truncated cone is a tall cylindar whose radius is 5cm. Liquid is being poured into the flask at a rate of 2cm^3/s. Note that the volume of a cone whose bottom radius is r and whose vertical hieght is h is given by v=(1/3)π(r^2)h.
I also know- bottom iare is V=(1/3)π(r^2)h-(1/3)π((10-.5h)^2)•(20h).
I have had a lot of problems with this, and if somebody could walk me through this, it would be much appriciated.
A) When the liquid is 15cmhigh in the flask, how fast is the height of the liquid increasing? (I don't think I need to worry about the cone for this one, becasue the water is already out of the cone)
B)If the flask is initially empty, how long does it take the liquid to reach a height of 10 cm?
C How fast is the height of the liquid rising when the liquid is 5cm deep.
2006-12-17
03:42:06
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2 answers
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asked by
jaywalkingjorn
2
in
Mathematics