HI! I'm pissed, as usual, about trigonometry. This time, it's about the reduction formula, a.k.a. the most idiotic thing I've ever seen in my life. I thought that all was fine, but now I've come across some real problems. First of all, my book does not explain how to use the reduction formula. All it does is give the formula and then show 1 problem worked out.
What I've surmised from that (and it has served me well thus far) is:
√(a² + b²)sin( x + α)
Great. I get the whole "√(a² + b²)sin( x" part, but I seem to be having trouble with the "+ α" aspect of it.
What I would guess, solely from my stupid book, is that to get α, you find cos α by doing a/[√(a² + b²)]. I need to know:
1) How do you know which value of α to use? Often times there is more than one angle for which cos = a/[√(a² + b²)].
2) What do you do when the problem is NOT in the form of a sin x + b cos x, but rather a sin x - b cos x? What about if a is negative?
Thank you so much! I'll pick a best answr!
2007-09-05
06:51:18
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2 answers
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asked by
Anonymous