Quadratic Question?

Question

I've got this quadratic to solve as part of a problem but can't do it- any help please?!
3s^2 - 925s + 7500 = 0
Obviously you need to use the general solution but I can't do this with b being negative. Please help.

Answer 1

a = 3
b = -925
c = 7500

b^2 - 4ac
= (-925)^2 - 4(3)(7500)
= 855625 - 90000
= 765625

-b +- sqrt (b^2 - 4ac)
= -(-925) +- sqrt 765625
= 925 +- 875
= 50 or 1800

[-b +- sqrt (b^2 - 4ac) / 2a
= (50 or 1800) / 2(3)
= (50 or 1800) / 6
= 50 / 6 or 1800 / 6
= 25/3 or 300

Answer 2

s= [925 +/- sqrt(925^2-4(3)(7500)]/(2*3)
s = (925 +/- 875)/6
s = 300 and 50/6 = 8 1/3

Answer 3

Rewrite the equation so that it looks like the standard form that you are used to:
3x^2 + (-925)x + 7500 = 0
x =
-(-925) ± √( (-925)^2 - 4 (3) (7500) )
-------------------------------------------------
2(3)

x =
925 ± √( 855625 - 90000 )
-------------------------------------------
6
x =
925 ± 875
---------------
6

x = 1800/6, 50/6
Answer: x = 300, 8 1/3

Answer 4

3s^2 - 925s + 7500 = 0

300 and 8.3333

Answer 5

a = 3
b = -925
c = 7500

zeroes = [-b ± sqrt(b² - 4 a c)] / [2 a]

x+ = [-b + sqrt(b² - 4 a c)] / [2 a]
x+ = [925 + sqrt(855625 - 90000)] / 6
x+ = [925 + 875] / 6
x+ = 300

x- = [-b - sqrt(b² - 4 a c)] / [2 a]
x- = [925 - sqrt(855625 - 90000)] / 6
x- = [925 - 875] / 6
x- = 8.3333333333333 or 25/3

MJ

Answer 6

ax^2+bx+c=0
x=[-b+sqrt(b^2-4ac)]/2a ---- (1)
x=[-b-sqrt(b^2-4ac)]/2a ---- (2)
a=3 b=-925 c=7500
b^2-4ac = 855625 - 90000=765625
sqrt(b^2-4ac)=875
(1) becomes [925 + 875]/6 =300
(2) becomes [925 - 875]/6 =50/6=25/3=8.33
300 and 8.33 (approximate) are solutions

Answer 7

You can use the quadratic equation even if b is negative. Here's a cool website I found that may help you calculate the answer (but it doesn't show you the work to solve it).

www.1728.com/quadratc.htm