The sales (S) of a product as a function of the time (t) (in weeks) is given by S=[2300(5t+1)] / (2t+5). Find the instantaneous rate of change of (S) with respect to (t) for t= 9 weeks.
2007-09-05 06:27:55 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
dS/dt = 2300 /(2t+5)^2 * [5(2t+5)-2(5t+1)] = 2300 *(23/(2t+5)^2)
For t= 9
dS/dt= 100
2007-09-05 07:33:17 · answer #1 · answered by santmann2002 7 · 0⤊ 0⤋
This has greater to do with vectors than Calculus. The boats on the component the place they're equidistant make an isosceles suited-angled triangle. because of the fact they're equidistant and shifting with consistent speed, and subsequently no exchange in speed(subsequently no room for calculus), subsequently the gap will have not have been given any effect on the end result . nevertheless i'm going to respond in a manner which you will comprehend. Boat A is crusing north with a speed of 13 mph, Boat B is crusing west with x mph. The relative speed is given via Vector of a - vector of b. this could provide us a line, whose magnitude is given via sqrt(a^2 + b^2) subsequently sqrt(13^2 + x^2) = relative speed = 17 this implies 13^2 + x^2 = 17^2 169+x^2=289 x^2=a hundred and twenty x=sqrt(a hundred and twenty) ....(i don't care what's this is fee because of the fact after all this is decrease than 13)
2016-11-14 06:40:11 · answer #2 · answered by ? 4 · 0⤊ 0⤋