Simplify:
cos(A+pi/2)+sin(A+pi/2)
2007-09-05 06:41:26 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
this is not calculus!
2007-09-05 06:46:13 · answer #1 · answered by U know who 3 · 0⤊ 4⤋
= cos A cos pi/2 - sin A sin pi/2 + sin A cos pi/2 + cos A sin pi/2
sin pi/2 = 1; cos pi/2 = 0, so...
= -sin A + cos A = cos A - sin A
2007-09-05 13:47:31 · answer #2 · answered by Mark H 3 · 0⤊ 1⤋
cos (a + b)
= cos a cos b - sin a sin b
sin (a + b)
= sin a cos b + cos a sin b
So...
cos (A + pi/2)
= cos A cos pi/2 - sin A sin pi/2
= (cos A)(0) - (sin A)(1)
= -sin A
sin (A + pi/2)
= sin A cos pi/2 + cos A sin pi/2
= (sin A)(0) + (cos A)(1)
= cos A
So...
cos (A + pi/2) + sin (A + pi/2)
= -sin A + cos A
= cos A - sin A
2007-09-05 13:47:37 · answer #3 · answered by Mathematica 7 · 1⤊ 1⤋
cos(A + pi/2) + sin(A + pi/2)
cosA.cos(pi/2) - sinA.sin(pi/2) + sinA.cos(pi/2) + cosA.sin(pi/2)
cosA . 0 - sinA . 1 + sinA . 0 + cosA . 1
cosA - sinA
2007-09-05 14:19:33 · answer #4 · answered by fortman 3 · 0⤊ 0⤋
cos(A+Ï/2) + sin(A+Ï/2) =
cos(A)cos(Ï/2) - sin(A)sin(Ï/2) + sin(A)cos(Ï/2) + cos(A)sin(Ï/2) =
cos(A)(0) - sin(A)(1) + sin(A)(0) + cos(A)(1) =
-sin A + cos A
2007-09-05 13:49:30 · answer #5 · answered by Philo 7 · 0⤊ 1⤋