huh? how do you do this again?

Question

The sum of twonumbers is33. Twice the first number minus the second number equals 18.Find both numbers

Answer 1

Let the numbers be x and 33-x
According to the problem,
2x-(33-x)=18
2x-33+x=18
3x=18+33=51
x=51/3=17
therefore,the numbers are 17 and 33-17 or 16

Answer 2

Okay, first assign variables to the numbers.
Let x = first number and y = second number.
You know: x + y = 33
2x - y = 18.
Now you just solve using the substitution or elimination methods.
Substitution:
Get one
x + y = 33
-x - x
y = 33 - x
Then substitute (33 - x) for y in the other equation.
2x - (33 - x) = 18
Distribute the - sign to both numbers inside the parenthesis.
2x -33 + x = 18
Combine the terms
3x - 33 = 18
Add 33 to both sides
3x - 33 = 18
+33 +33
3x = 51
Then divide both sides by 3.
3x = 51
x = 17.
Now just substitute the x with 17 in one of the original equations.
(17) + y = 33
Subtract by 17 on both sides.
17 + y = 33
-17 -17
y = 16
x = 17
Therefore the first number is 17 and the second number is 16.
Sorry it's so long, I hope it helps.

Answer 3

Hi,

You need to use algebra.

Let the first number = x.
Let the second number = y.

x + y = 33
2x - y = 18

If x + y = 33, x = (33 - y)

Substitute for x using y in the second equation.

2(33 - y) - y = 18
66 - 2y - y = 18
-3y = -48
so y = 16.

If y = 16, x = (33 - 16) = 17.

x = 17, y = 16.

Hope this helps.

Answer 4

x+y=33
2x-y=18

You want to add these, so re-write the sum of these as:

3x=51
x=17

Rewrite to solve for y:
2x-y=18, 2x=18+y, 2x-18=y.
If x=17, then 2(17) -18 = y, 34-18=16.

Then y=16

Let's fill into the first equation:
x+y=33. Do 16+17 = 33. Yes!! It works.

Answer 5

x + y = 33
2x - y = 18
Adding both equations gives:
3x = 51
or
x = 17
Another number is
y = 33 - 17 = 16

Answer 6

x + y = 33
2*x - y = 18
---------------- +
3x = 33 + 18
x = 11 + 6 = 17
y = 33-17 = 16

Answer 7

x+y=33
2x-y=18
solve them now.
i have formed the eqn

Answer 8

okay i am sorry i don't know