There are three problems that follow this, they are what needs to be solved. I am so confused. If you would like a link to the image of the problems instead than reading this, you can find the exact same information at the far bottom of the image here http://palcs.digitalschooling.com/brand/media/images/1193//Algebra_2/New%20Algebra%202/New%20Lessons/homework%20lesson%2012.JPG
Since you don't know whether X is positive or negative, you have to consider two cases: (part 1) X > 0 or (part 2) X < 0.
Part 1.) X > 0
Multiply both sides of the given inequality by 2x, which is positive.
10+x < 6x => 10 < 5x => 2 < x
In this case, the solution is x > 0 and x > 2, or x > 2.
Part 2.) X < 0
Proceeding as before, except that now 2x is negative, you have
10+x > 6x => 10 > 5x => 2 > x
The solution is x < 0 and x < 2, or x < 0.
[[[A / indicates a fraction]]]
Problem a.) 11/3 - 2/x > 5
Problem b.) 8/x - 7 < 9
Problem c.) 3/4 + 12/x-1 > 1
Thanks so much in advance.
2006-10-13
16:41:00
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5 answers
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asked by
Ryan
1
in
Mathematics