Jenny has 32 coins worth P128. Some are 5 pesos coin & the rest are 1 peso. How many of each coins she has?

Question

Thank u!

Answer 1

Let x = number of 5P coins, and y = number of 1P coins.

Then x+y=32, and 5x+1y=128

From the first equation, y = 32-x. Substituting that into the second eqn., you get: 5x + 32 - x = 128

This simplifies to 4x + 32 = 128
4x = 96
x = 24
Since x+y = 32, then y = 8.
So there are 24 5P coins, and 8 1 Peso coins.

Answer 2

You know there are 32 coins and the total is 128.

Let v=the number of 5 peso coins
therefore 32-v must equal the number of one peso coins
thus the equation: 5v+(32-v)=128
now simplify:
5v+32-v=128
5v-v+32=128
4v+32=128
4v+32-32=128-32
4v=96
v=24
therefore there are 24 5 peso coins, which means the rest, 8, must be 1 peso coins

Answer 3

Truthfully i didn't use my math to get an answer. I used a spreadsheet.
A1= # of 5 pesos
B1= A1*5
A2=32-A1
B2=128-B1
Then I just pushed in numbers in A1 until A2=B2

Or you could do it *right*.
n=number of pesos
f=number of 5 pesos
f + n = 32 n = 32- f
5*f + n = 128

5f + (32 -f) = 128
4f+ 32 = 128
4f = 96
f = 24
24 + n = 32
n = 8
So, 24 5 pesos and 8 pesos

Answer 4

wow u r doing your homework isnt that cheating