The question I am given is: "A basketball star covers 2.60 m horizontally in a jump to dunk the ball (see figure). His motion through space can be modeled as that of a particle at a point called his center of mass (which we shall define in Chapter 9). His center of mass is at elevation 1.02 m when he leaves the floor. It reaches a maximum height of 1.80 m above the floor and is at elevation 0.850 m when he touches down again."
And i need to find the time of flight, the initial horizontal/vertical velocity, and angle.
However, I am pretty clueless how to find the total time. I figured x(final)=.5at^2 So sqrt((0.95*2)/a)=time, but 0.44, the answer i get (times two, so 0.88) isn't the overall hang time. Now i'm just completely lost.
2007-09-23
04:06:16
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2 answers
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asked by
phrozenwarrior
3
in
Physics