...by heating with a Bunsen burner? In each case, explain your answer.
Ethyl alcohol (bold) in whiskey
CuSO4.4H2O/HgO (bold)
KClO3/CaCO3 (bold)
Hints:
1. Water of hydration (as in CuSO4.4H2O) can be driven out by strong heating.
2. When HgO is heated, it decomposes to Hg(l) and O2(g).
3. Carbonates (as in CaCO3) decompose upon heating yielding a metal oxide plus CO2(g).
Just for clarification, the target compounds in bold are ethyl alcohol, HgO, and CaCO3. For ethyl alcohol, maybe you could just use its empirical formula C2H6O.
2007-01-29
03:18:32
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1 answers
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asked by
trypanophobic34
2
in
Chemistry