During a volcanic eruption, chucks of solid rock can be blasted out of the volcano; these projectiles are called volcanic blocks. Rock is blasted at an elevation of 3300 meters at an angle of 35 degrees.
a) At what initial velocity would a block have to be to be ejected, at 35 degrees to the horizontal, from the vent to the foot of the volcano 9400 meters away?
b) What is the time of flight?
I can do B, but I dunno how to find initial velocity, most of the problems I did with projectile motion already gave me initial velocity. Here's what I did:
I used the formula y-y(0)=vt-1/2at^2. I'm going to assume the final velocity of this whole thing is 0, and gravity is -9.8m/s^2, so:
-3300=-4.9t^2; t=26
I used that "t" to plug into: v=v(0)+AT
0=v(0)-9.8(26); V(0)=255 m/s. The answer that the book got was 260 m/s, can anyone show me what I did wrong and how to do the problem? Thanks!
2007-09-16
18:42:19
·
3 answers
·
asked by
Anonymous