physics quick calculation to kilowatt?

Question

The actual efficiency of the engine is 42.0%. How much useful power does the engine deliver if it takes in 1.15 10^5 J of energy each second from its hot reservoir?

i did the calculation (0.42) * (1.15 10^5 J ) and got 48300 joules and cannot figure out how to get it to kilowatt not kwh just kW is what the site asks for

Answer 1

its says 1.15*10^5 J/s=1.15*10^5 W, since one watt is one joule per second.

if you got 48300 joules per second, it is 48.3 kW

Answer 2

One joule per second is one watt. 10^3 joules per second is a kilowatt. Your calculation really results in joules per second, since the input energy rate is given as 1.15*10^5 joules per second (joules of energy each second). This value is equivalent to 1.15*10^5 watts, or 1.15*10^2 kilowatts. Therefore your answer is 48300 watts, or 48.3 kilowatts.

Answer 3

I'm sorry but you can get 48300 joules to kW( one thousand joules per second).

Answer 4

Gravity - -9.8 m/s^2 time = 2.8s comprehensive flight, so it takes one million.4 s to realize the apex of the flight. so the preliminary speed of the dart is (one million.4s)(9.8m/s^2) = 13.72m/s all of us comprehend that best distance that is carried out by a prjectile occurs whilst that's fired at 40 5 degree attitude. So we could verify the vertical and horizontal velocities whilst fired at a 40 5 degree attitude. which will use pyhtagorean theorem to verify he different 2 factors h^2 = o^2+a^2 o=a h^2=2a^2 h=root(2)a a=o=h/root(2)=13.seventy two/root(2)=9.701 so this is going to fly for 9.701/9.8 seconds = .ninety 9 sec .99s*9.701m/s = 9.6 m this is going to fly 9.6 m. (31.5 ft)

Answer 5

You wont be able to change Joules to Kilowatts

Answer 6

Here's my working for your reference.

Power input = energy input per unit time = 1.15x10^5 Js^(-1) = 1.15x10^5 W = 11.5kW

Useful power output = efficiency x power input
Thus, useful power output = 42.0% x 11.5kW = 4.83kW