"In car batteries, 6.0 M sulfuric acid is used. If you purchase 18.0 M sulfuric acid, how could you dilute the concentrated acid to get the right molarity if you needed 2.0 liter of the 6.0 M battery acid?"
The calculation:
(2 liters) x (6.0M / 18.0M) = 0.67 L of 6.0M sulfuric acid.
So,
You add 0.67 L of 18.0M sulfuric acid into a flask, add water until the solution is 2L.
Okay, my problem is that I don't understand the calculation. Where does the "(6.0 M / 18.0 M)" come from / what is the reasoning behind everything?
Thanks in advance!
2007-06-09
08:00:43
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5 answers
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asked by
Paul
3