i was thinking about the 35 to 1 odds on roulette....i played one dollar on numbers 1 to 35 (leaving 0,00, and 36 open) to make one dollar.....if 0,00, or 36 came out i put 10 bucks on numbers 1 to 32 (leaving 33,34,35,36,0,00 open) to make 5 bucks (40 - 35 loss from previous spin = 5 won) and if one of those 6 numbers came out i press it one more time to 100 bucks on numbers 1 to 32 (leaving 33,34,35,36,0,00 open again to make 45 bucks 3500 for win 00 minus 35 bucks loss (level 1) + 320 bucks loss (level 2) = 355 you made 400 on spin in level 3 (leaving 3 open + 100 under glass) to make 400 bucks which covers 35 + 320 = 355 which means you made 45 bucks on the 3rd spin
Therefore I play it like this and win consistently
Level 1
1 to 35 (0,00,36) one dollar each spot
total made 1 dollar
Level 2
1 to 32 (33,34,35,36,0,00) 10 dollars each spot
total made 5 dollars
Level 3
1 to 32 (33,34,35,36,0,00) 100 dollars each spot
total made 45 dollars
I stay at level 1 if i win
2007-12-27
08:05:48
·
14 answers
·
asked by
Anonymous