A dive bomber has a velocity of 280 m/s at angle 'theta' below the horizontal. When then altitude is 2.15 km, it releases a bomb, which subsequently hits a target on the ground. The magnitude of displacement from the release of the bomb to the target is 2250m, find theta.
I usually do not ask from homework help, but I have been working on this one for a while and I am still not sure how to approach it. Thanks everyone.
2006-09-10
16:11:16
·
5 answers
·
asked by
three_holepunch_haircut
2