The ? is :
1a. what is the mass of the air in a physics classroom that is 8.0 m wide, 10.0 m long, and 2.8 m high?(the mass density of air is 1.29 g/dm^3).
1b. If the mass density of lead is 11.4 g/cm^3, what volume would be occupied by the same mass of lead?
My work: ......since V=WxLxH and D=M/V
1a. 8.0m x 10.0m x 2.8m= 224m^3=V
1.29 g/dm^3= m / 224m^3
1.29 g/dm^3=.00129g/m x 224m^3= 2.9 x 10^-1 is the mass
1b. D=M/V
11.4g/cm^3=2.9 x10^-1g/m^3/V
11.4g/cm^3=.114g/m^3
so .114g/m^3 x V=2.9 x10^-1g/m^3
V=2.9x10^-1g/m^3 / .114g/m^3
V=2.54 g???
Am i right or did i make any mistake in units or calculations anywhere?
2006-09-26
07:05:26
·
2 answers
·
asked by
dreamz
4